From: JoeBiden.com
Date: Tue, Mar 3, 2020 at 11:38 PM
Subject: Bernie Sanders
To: ajay mishra

This week, Bernie Sanders’ campaign reported that they raised a staggering $46 million in February.

‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ajay — we know we keep emailing you and asking you for $5. Here’s why: this week, Bernie Sanders’ campaign reported that they raised a staggering $46 million in February. And while that might seem like bad news, we actually have a real chance to compete against this latest haul. Look, given our surge in small-dollar fundraising following our win in South Carolina, we are in a better position than ever before to compete head-to-head against the Sanders campaign’s money. But, we have to keep closing the money gap before polls close tonight, and that’s where you come in, ajay. If you pitch in $5 before the polls close tonight, we’ll be in a terrific position to win tonight in Super Tuesday states and beyond » Countdown Until the First Polls Close Tonight Donor Record for ajay mishra ZIP: 78746 Donated to Joe Biden? No, not yet Suggested Action? Pitch in $5 before polls close tonight » If you’ve saved payment information with ActBlue Express, your donation to Joe Biden will go through immediately: Chip in $5 ➞ Chip in $25 ➞ Chip in $50 ➞ Chip in $100 ➞ Chip in $250 ➞ Or donate another amount ➞ Let’s make sure that we have every resource at our disposal to win tonight and keep the momentum going, ajay! Pitch in what you can today: https://go.joebiden.com/Donate Thank you, JoeBiden.com

Any donor history information in this email reflects what we have on file for this specific email address. If you have donated with a different email, with a check, or with a spouse — thank you so much! We have that on file and cannot thank you enough for supporting this campaign. This email was sent to ajayinsead03. If we got your name or any information wrong — we’re so sorry! To update and correct your information click here. If you would like to receive fewer emails, click here. If you would like to unsubscribe, click here. ajay, thank you so much for supporting Joe Biden’s Presidential campaign. This isn’t the time to be complacent. If you are ready to fight for the soul of this nation, you can start by donating to elect Joe Biden by clicking the button below. DONATE TO ELECT JOE BIDEN » We know we send a lot of emails, and we are sorry about that. The reason? We are relying on grassroots supporters like you (we’re serious!). But ajay, we don’t want to bother you. If you’d like to only receive our most important emails, click here. If you’d only like to receive volunteer emails, click here. If you’d like to unsubscribe from our emails, you can click here. To make a contribution by mail, click here for instructions. We sincerely thank you for your help and support. – The entire Joe Biden for President team Paid for by Biden for President

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https://www.google.com/search?q=FROM+OLGA+LEDNICHENKO+TO+BILL+CLINTON+I+THINK+ABOUT+MAKE+-+MODEL+AND+MATERIAL+OF+MY+TABLE+AND+COMPARE+IT+WITTH+THAT+OF+OTHER+PEOPELS%3B+KITCHEN+TBALES+-+IS+THIS+A+GOOD+SUMMARY+FOR+MALES+AND+U+%3F+&tbm=isch&ved=2ahUKEwjyjOWo8f7nAhUU4DgGHaezDxgQ2-cCegQIABAA&oq=FROM+OLGA+LEDNICHENKO+TO+BILL+CLINTON+I+THINK+ABOUT+MAKE+-+MODEL+AND+MATERIAL+OF+MY+TABLE+AND+COMPARE+IT+WITTH+THAT+OF+OTHER+PEOPELS%3B+KITCHEN+TBALES+-+IS+THIS+A+GOOD+SUMMARY+FOR+MALES+AND+U+%3F+&gs_l=img.3…23168.24492..25038…0.0..0.0.0…….0….1..gws-wiz-img.NIaeuiss01A&ei=S5teXrK7EJTA4-EPp-e-wAE&bih=758&biw=1519&hl=en#imgrc=Q3hN9l7QB9RWiM

[1]

[2]

[3]

CLICKS THIS

I LIKE JOE BIDEN AND KAMALA HARRIS

From: for Ajay’s eyes only
Date: Tue, Mar 3, 2020 at 11:01 PM
Subject: Super Tuesday: Official Texas Straw Poll
To: Ajay Mishra

We need [23] responses by 11:59pm.

‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ End Citizens United is dedicated to electing Democrats, transforming our broken campaign finance system, and ultimately ending Citizens United. If you really want to receive only our most urgent emails or unsubscribe, click here. ➤➤ RESPOND NOW: Begin Official Super Tuesday Straw Poll >> Ajay: You have been selected to take our Official Super Tuesday Straw Poll >> Super Tuesday is TODAY. The candidate who wins the most states today is likely to be the Democratic nominee. So we are polling Austin, Texas Democrats on their preferences, but our poll closes tonight at 11:59 PM. 8 Democratic candidates are running to defeat Trump, but it remains unclear who has the most support among End Citizens United members. Begin your official Straw Poll to let us know your 2020 choice: BEGIN OFFICIAL 2020 STRAW POLL >> NAME: AJAY MISHRA STATUS: TOP DEMOCRAT It’s essential we get your response to know who top Democrats from Texas are supporting in the Presidential Primary in order to beat Trump in 2020. And Ajay, you were selected as one of our top Texas Democrats to take our Official 2020 Straw Poll right now. So don’t delay: BEGIN OFFICIAL 2020 STRAW POLL >> Thank you for your valuable input, -End Citizens United Research Team

This message was sent to: ajayinsead03@gmail.com Click here to receive fewer emails. | Click here to unsubscribe.

Thank you for supporting End Citizens United PAC. Our entire team is working to the bone to pass SWEEPING Campaign Finance Reform — the future of our Democracy depends on it: DONATE TO END CITIZENS UNITED ➞ When we pass the Constitutional Amendment to overturn Citizens United, our movement will go down in history as HEROES. And Ajay, when the next generation asks what you did to stop Donald Trump, you’ll be able to say you were a Proud Member of End Citizens United. We know we send a lot of emails. And you might be wondering why: We aren’t a SuperPAC. We’re not funded by billionaires. We rely on Democrats giving an average gift of $13 to emails like this to fuel our entire operation. We spend EVERY DIME so efficiently by running proven effective ads to win the most competitive races, pushing HARD to pass Sweeping Campaign Finance Reform, and building our movement. However, if you’d like to receive fewer emails, you can click here. If you’d like to unsubscribe from our emails, click here. If you’d like to donate to help fund our efforts to fix America’s broken campaign finance system, please click here. From the entire End Citizens United team, thanks for your support!

I THINK ANYONE WHO SAYS KITCHEN TABLE ISNT IMORTNT IS DENYING THEIR OWN FAMILY

AND

THSOE WHO SAY MENDELEEV TBLE CAN BE COMLETELY UNEARTHEED HAVE TO LOOK AT SOME OTHER BACK YARDS

AND ALSO, ITS ALSO IMORTANT THE SIZE OF THE KITCHEN TABLE – MENAING – ARE WE FEEL COMFORTABLY NUMB THET

[A] SOME PEOPLE ARE HAVING FOOD FIGHTS AT THE JITCHEN TABLE

OR

[B] SOME PEOPLE ARE JIST AFRAIF OF INCREAISING THE SIZE OF THEIR EXISTING TABLE – BECAUSE – KIDS MEANS DIAPRES AND NAPKINS – AND THEIR COST HAS GONE THRU THE ROOF

OR

[C] SOME PEOPLE CANT AFFROD BEYOND THE SYTLE OF THEIR KICTHEN TABLE, BECAUS ETHE UDBUDEGT LINE IS MAKING DEMANDS ON THE OTHER SIDE

OR

[D] SOME PEOPLE ARE WONDERING IF OTHERS ON THE OTHER SIDE OF FLORIDA’S KEY WEST AND HAWAII’S WEST – ARE HAVING ENOUGH ON THERI TABLE, SO AS TO NOT REACH A TAGE OF DEPSRETATON – SO MUCH SO THAT OUR KISTCHJENS MAY BE DEMOMOLISHED BY AN ANGRY MOB, OUT SIDE OUR FRONT OR BACK YARD

OR

[E] SOME PEOPLE ARE WORRIED THAT – WHILE WE SIT IN OUR ARMS CHAIRS AND SVIVEL AROUND LIKE A MAFIA DON – ARE WE COGNIZANT ABOUT THE TABLES AND CHAIRS –

IN OTEHR PEOPELS HOMES HOMES THEY CALL TEHRI WON AND HAVE PROBLEMS IF YOU ARE INSENSITIVE OR NOT INCENTIVIZED BCEUA EOF OTEITEHR MOON

OR THE VOTE BACK OF YOUR RBOWN AND LIBERAL LEFT OR – FEARFUL THAT YOUR MACHO – MARLBOROO, MEN LIKE TO PALY RUSSION ROULELTTE IN MIDEDLE EASTA DN AFGHAN AND ALL YOU CARE OF IS YOUR TBLES AND YOUR KITCHNE NOT THEIRS

OR

[6] ALL OF THE ABOVE AND MORE ITEMS SONGS – I CAN ADD BUT THE ABOVE 6 – IS ENOUGH FOR EME TO CHEW ON..

AS A GIRL, IHAVE FOUND AMERICAN MEN TO BE HIGH OF TESTOSTRRSTERONE AND ON BOMBSTIC WORDS,

BUT MAY I DARE SAY WE HAVE A WORD CALED M FOR MENSCH ALSO – NOT JSJST M FOR MARLBORO MAN –

MAY BE DOUG CAN EXPLAIN WHY JEWISH MEN ARE SOFT, AND SWEET AND COTTON AND CANDY AND WHILE ST TRUE THAT THEY ARENT AS MACHO – AS IS THE BROWN MEDIVIAL MAN – BUT ITS A TARDE OFF – ANY GIRL CAN MAKE :

I HOPE U TAKE THAT AS A COMPLIMENT – AND YES, U HAVE A SOULFUL FACE – BUT THE JEW – CAME ON THE STAGE TO PROETCT YOU FROM ROWDY LIBERAL LEFT OF THE LEFT – ANARCH MAN

HOPE THIS IS ENOUGH FOR AN EVENING : MATCH

REGARDS

OLGA – THE RUSSHIAN – THE ONE WHO HAS ENOUGH TESTOSTERONE SUPPLIED BY A MARLBRO MAN TO LAST A LIFE TIME FOR THE JEW AND THE SISSY TRIBE -:)

PPS: I THINK THIS TIME YOU DINT OOZE GARANDISSONEESS AND CONFINED YOURSEELDF TO BEING A PROSECTOR –

AND DONT THEY SAY – IN USA – ALL FOREIGNES SAY – THEY DREAM BIIIIIIIIIIIG LIKE EVERYTHING IS BIG IN TEXAS –

LIKE WITH BARACK – IT WA S GREEK COLOLUMN WITH OPRAH CYRING WHEN HE SAID MOON AND THE TIDES AND LAWRENCE OF ARABAI , GANDHI, GODFATEHR, AND CABALANCA IN THE SAME LINE

From: Team Kamala
Date: Tue, Mar 3, 2020 at 10:25 PM
Subject: Tell Kamala which one of these issues is most important to you >>
To: Olga Shulman Lednichenko

ᐧ

HERE IS SOME QUIZ HELP

HERE

AND SEE HERE

http://yoninetanyahu.com/wp-content/uploads/2020/03/WHO-IS-BLUE-AND-BLONDE.jpg

 https://www.youtube.com/watch?v=VrsLXWGtRcs

HERE IS SOME QUIZ HELP

HERE

AND SEE HERE

http://yoninetanyahu.com/wp-content/uploads/2020/03/WHO-IS-BLUE-AND-BLONDE.jpg

From: Zillow
Date: Tue, Mar 3, 2020 at 9:31 PM
Subject: Your Home Report for 1909 Payne Ave – Zestimate and Neighborhood Updates
To:

The latest data on your home and real estate activity near you.

Zestimate: $404,958 1909 ‌Payne ‌Ave, ‌Austin, ‌TX 2 bd, 1 ba, 720 sqft Off Market See how it changed Check out your news feed 6309 Burns St # C-201 listed for rent for $1,299/mo 1mi away • 40m ago 6309 Burns St # D-307 listed for rent for $1,369/mo 1mi away • 41m ago 2211 W North Loop Blvd APT 223 listed for rent for $999/mo 1mi away • 11h ago View More Median Neighborhood Zestimate +0.8% past 30 days $476,800 Learn more Just Listed $380,000 3 bd | 2 ba | 1,204 sqft Austin $465,000 4 bd | 1 ba | 1,430 sqft Austin $899,000 4 bd | 3 ba | 2,300 sqft Austin View More Sold Nearby $389,000 3 bd | 2 ba | 1,102 sqft Austin $845,292 4 bd | 3 ba | 1,892 sqft Austin View More Zillow, ‌Inc. 1301 ‌Second ‌Avenue, ‌Floor ‌31 Seattle, ‌WA ‌98101 © ‌2006‌-‌2020 Privacy policy | Unsubscribe from this email | Update your preferences

ᐧ

HELLO KAJASRTA

WHERE IS KJAKARTA BUBBA

OLGA AND SANJAY AND ALINA AND CHISTINA, HWERE IS KAKARTA ?

[youtube http://youtube.com/w/?v=6D9vAItORgE]

HWREE IS JAKARTA?

[youtube http://youtube.com/w/?v=Zn8q0LsO4PA]

OH HERE IS JAKARTA ?

[youtube http://youtube.com/w/?v=qOSwBIstZUs]

HWREE IS JAKARTA?

OH HERE IS JAKARTA ?

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From: Streak
Date: Tue, Mar 3, 2020 at 9:56 PM
Subject: Someone just viewed: BHULEKH Uttar Pradesh खाता विवरण (अप्रमाणित प्रति) ग्राम का नाम : बक्कास परगना : (मोहनलालगंज) तहसील : मोहनलालगंज जनपद : लखनऊ फसली वर्ष : 1423-1428 भाग : 1 खाता संख्या : 00074 खातेदार का नाम / पिता पति संरक्षक का नाम / निवास स्थान खसरा संख्या क्षेत्रफल (हे.) आदेश टिप्पणी श्रेणी : 1-क / भूमि जो संक्रमणीय भूमिधरों केअधिकार में हो। ओम प्रकाश श्रीवास्तव / स्व.एफ.पी.श्रीवास्तव / म.न.ए.706 से. सी.महानगर लखनऊ श्रीमती रेनू �
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Someone just viewed: ” BHULEKH Uttar Pradesh खाता विवरण (अप्रमाणित प्रति) ग्राम का नाम : बक्कास परगना : (मोहनलालगंज) तहसील : मोहनलालगंज जनपद : लखनऊ फसली वर्ष : 1423-1428 भाग : 1 खाता संख्या : 00074 खातेदार का नाम / पिता पति संरक्षक का नाम / निवास स्थान खसरा संख्या क्षेत्रफल (हे.) आदेश टिप्पणी श्रेणी : 1-क / भूमि जो संक्रमणीय भूमिधरों केअधिकार में हो। ओम प्रकाश श्रीवास्तव / स्व.एफ.पी.श्रीवास्तव / म.न.ए.706 से. सी.महानगर लखनऊ श्रीमती रेनू प्रकाश / ओ.पी. श्रीवास्तव / नि. A 706 सेक्टर सी महानग र लखनऊ प्रमोद कुमार सोनकर / विश्वनाथ सोनकर / 164/54अस्तबल मौलवीगंज चारबाग लखनऊ 750 0.8790 आदेश ना.तह.गोसाईगंज वाद स.टी-20161046390311136/5.12.16 खाता स.74 गाटा स.750/0.879हे. का 1/4 भाग रकबा 0.21975हे. विक्रेता के सम्‍पूर्ण अंश मा.गु.60ख से विक्रेता प्रमोद कुमार सोनकर पुत्र विश्‍वनाथ सोनकर नि.164/54 अस्‍तबल मौलवीगंज चारबाग लखनऊ का नाम खारिज करके क्रेता कमलेश कुमार पुत्र स्‍व.रामप्रसाद नि.दुल्‍लापुर पर. व तह. मोहनलालगंज लखनऊ का नाम जरिये बैनामा दि.15.10.16 दर्ज हो । ह.र.का./6.1.17 न्‍यायालय असिस्‍टेन्‍ट कलेक्‍टर प्रथम श्रेणी मोहनलालगंज लखनऊ वाद स.टी-2017104639038182 ता.फै.15.9.17 धारा 80 उ.प्र.राजस्‍व संहिता 2006 कमलेश बनाम सरकार ग्राम बक्‍कास वादीय भूमि गाटा स.750/0.879हे. का 1/4 भाग मे से रकबा 0.0523हे. स्थित ग्राम बक्‍कास को मा.गु.60ख से मुक्‍त करते हुये प्रश्‍नगत भूमि अकृषित घोषित की जाती है। ह.र.का./9.10.17 आदेश तहसीलदार मोहनलालगंज वाद सं.टी-2017104639037402/18.10.17 गाटा सं.750/0.879 का 1/4 भाग रकबा 0.2197हे.मे से 0.1672हे. मा.गु.60 से विक्रेता कमलेश कुमार पुत्र स्‍व.रामप्रसाद नि.दुल्‍लापुर का नाम खारिज करके क्रेता पप्‍पू रावत पुत्र स्‍व.हरदयाल नि.सरसवां अर्जुनगंज तहसील सरोजनीनगर लखनऊ का नाम जरिये बैनामा दि.19.8.17 दर्ज हो।ह.र.का/28.11.17 आदेश न्‍यायालय असिस्‍टेन्‍ट कलेक्‍टर प्रथम श्रेणी मोहनलालगंज लखनऊ वाद सं.टी-20171046390311678, 581/16-17 दि.30.12.17 धारा-80 उ.प्र. राजस्‍व संहिता 2006 पप्‍पू रावत बनाम सरकार ग्राम बक्‍कास वादीय भूमि खाता सं.74 गाटा सं.750/0.879हे. मे से रकबा 0.1672हे. स्थित ग्राम बक्‍कास पर. व तह.मोहनलालगंज लखनऊ को मालगुजारी 60ख से मुक्‍त करते हुये प्रश्‍नगत भूमि को कृषि प्रयोजन से भिन्‍न प्रयोजन की भूमि(अकृषिक) घोषित किया जाता है।ह.र.का./15.1.18 750मि./0.293 ओम प्रकाश श्रीवास्तव के हिस्से की भूमि अकृषिक घोषित। (धारा 143) योग 1 0.8790 कृपया उक्त खसरे की प्रस्थिति (भूखंड (गाटा) के वाद ग्रस्त /विक्रय /भू-नक्शा ) हेतु खसरा संख्या पर क्लिक करें Disclaimer: उक्त आँकडे मात्र अवलोकनार्थ हैं, तहसील कम्प्यूटर केन्द्र एवम सी.एस.सी/लोकवाणी केन्द्र से उद्धरण की प्रमाणित प्रति प्राप्त की जा सकती है । Software Powered By: National Informatics Center, Uttar Pradesh State Unit, Lucknow. “

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The first axiom states that the constant 0 is a natural number:

The next four axioms describe the equality relation. Since they are logically valid in first-order logic with equality, they are not considered to be part of “the Peano axioms” in modern treatments.^[5]

The remaining axioms define the arithmetical properties of the natural numbers. The naturals are assumed to be closed under a single-valued “successor” function S.

Peano’s original formulation of the axioms used 1 instead of 0 as the “first” natural number.^[6] This choice is arbitrary, as axiom 1 does not endow the constant 0 with any additional properties. However, because 0 is the additive identity in arithmetic, most modern formulations of the Peano axioms start from 0. Axioms 1, 6, 7, 8 define a unary representation of the intuitive notion of natural numbers: the number 1 can be defined as S(0), 2 as S(S(0)), etc. However, considering the notion of natural numbers as being defined by these axioms, axioms 1, 6, 7, 8 do not imply that the successor function generates all the natural numbers different from 0. Put differently, they do not guarantee that every natural number other than zero must succeed some other natural number.

The intuitive notion that each natural number can be obtained by applying successor sufficiently often to zero requires an additional axiom, which is sometimes called the axiom of induction.

The induction axiom is sometimes stated in the following form:

In Peano’s original formulation, the induction axiom is a second-order axiom. It is now common to replace this second-order principle with a weaker first-order induction scheme. There are important differences between the second-order and first-order formulations, as discussed in the section § Models below.

Arithmetic[edit]

The Peano axioms can be augmented with the operations of addition and multiplication and the usual total (linear) ordering on N. The respective functions and relations are constructed in set theory or second-order logic, and can be shown to be unique using the Peano axioms.

Addition[edit]

Addition is a function that maps two natural numbers (two elements of N) to another one. It is defined recursively as:

{\displaystyle {\begin{aligned}a+0&=a,&{\textrm {(1)}}\\a+S(b)&=S(a+b).&{\textrm {(2)}}\end{aligned}}}

For example:

{\displaystyle {\begin{aligned}a+1&=a+S(0)&{\mbox{by definition}}\\&=S(a+0)&{\mbox{using (2)}}\\&=S(a),&{\mbox{using (1)}}\\\\a+2&=a+S(1)&{\mbox{by definition}}\\&=S(a+1)&{\mbox{using (2)}}\\&=S(S(a))&{\mbox{using }}a+1=S(a)\\\\a+3&=a+S(2)&{\mbox{by definition}}\\&=S(a+2)&{\mbox{using (2)}}\\&=S(S(S(a)))&{\mbox{using }}a+2=S(S(a))\\{\text{etc.}}&\\\end{aligned}}}

The structure (N, +) is a commutative monoid with identity element 0. (N, +) is also a cancellative magma, and thus embeddable in a group. The smallest group embedding N is the integers.

Multiplication[edit]

Similarly, multiplication is a function mapping two natural numbers to another one. Given addition, it is defined recursively as:

{\displaystyle {\begin{aligned}a\cdot 0&=0,\\a\cdot S(b)&=a+(a\cdot b).\end{aligned}}}

It is easy to see that S(0) (or “1”, in the familiar language of decimal representation) is the multiplicative right identity:

a · S(0) = a + (a · 0) = a + 0 = a

To show that S(0) is also the multiplicative left identity requires the induction axiom due to the way multiplication is defined:

• S(0) is the left identity of 0: S(0) · 0 = 0.
• If S(0) is the left identity of a (that is S(0) · a = a), then S(0) is also the left identity of S(a): S(0) · S(a) = S(0) + S(0) · a = S(0) + a = a + S(0) = S(a + 0) = S(a).

Therefore, by the induction axiom S(0) is the multiplicative left identity of all natural numbers. Moreover, it can be shown that multiplication distributes over addition:

a · (b + c) = (a · b) + (a · c).

Thus, (N, +, 0, ·, S(0)) is a commutative semiring.

Inequalities[edit]

The usual total order relation ≤ on natural numbers can be defined as follows, assuming 0 is a natural number:

For all a, b ∈ N, a ≤ b if and only if there exists some c ∈ N such that a + c = b.

This relation is stable under addition and multiplication: for {\displaystyle a,b,c\in \mathbf {N} }, if a ≤ b, then:

• a + c ≤ b + c, and
• a · c ≤ b · c.

Thus, the structure (N, +, ·, 1, 0, ≤) is an ordered semiring; because there is no natural number between 0 and 1, it is a discrete ordered semiring.

The axiom of induction is sometimes stated in the following form that uses a stronger hypothesis, making use of the order relation “≤”:

For any predicate φ, if

• φ(0) is true, and
• for every n, k ∈ N, if k ≤ n implies that φ(k) is true, then φ(S(n)) is true,

then for every n ∈ N, φ(n) is true.

This form of the induction axiom, called strong induction, is a consequence of the standard formulation, but is often better suited for reasoning about the ≤ order. For example, to show that the naturals are well-ordered—every nonempty subset of N has a least element—one can reason as follows. Let a nonempty X ⊆ N be given and assume X has no least element.

• Because 0 is the least element of N, it must be that 0 ∉ X.
• For any n ∈ N, suppose for every k ≤ n, k ∉ X. Then S(n) ∉ X, for otherwise it would be the least element of X.

Thus, by the strong induction principle, for every n ∈ N, n ∉ X. Thus, X ∩ N = ∅, which contradicts X being a nonempty subset of N. Thus X has a least element.

First-order theory of arithmetic[edit]

All of the Peano axioms except the ninth axiom (the induction axiom) are statements in first-order logic.^[7] The arithmetical operations of addition and multiplication and the order relation can also be defined using first-order axioms. The axiom of induction is in second-order, since it quantifies over predicates (equivalently, sets of natural numbers rather than natural numbers), but it can be transformed into a first-order axiom schema of induction. Such a schema includes one axiom per predicate definable in the first-order language of Peano arithmetic, making it weaker than the second-order axiom.^[8] The reason that it is weaker is that the number of predicates in first-order language is countable, whereas the number of sets of natural numbers is uncountable. Thus, there exist sets that cannot be described in first-order language (in fact, most sets have this property).

First-order axiomatizations of Peano arithmetic have another technical limitation. In second-order logic, it is possible to define the addition and multiplication operations from the successor operation, but this cannot be done in the more restrictive setting of first-order logic. Therefore, the addition and multiplication operations are directly included in the signature of Peano arithmetic, and axioms are included that relate the three operations to each other.

The following list of axioms (along with the usual axioms of equality), which contains six of the seven axioms of Robinson arithmetic, is sufficient for this purpose:^[9]

• {\displaystyle \forall x\ (0\neq S(x))}
• {\displaystyle \forall x,y\ (S(x)=S(y)\Rightarrow x=y)}
• {\displaystyle \forall x\ (x+0=x)}
• {\displaystyle \forall x,y\ (x+S(y)=S(x+y))}
• {\displaystyle \forall x\ (x\cdot 0=0)}
• {\displaystyle \forall x,y\ (x\cdot S(y)=x\cdot y+x)}

In addition to this list of numerical axioms, Peano arithmetic contains the induction schema, which consists of a recursively enumerable set of axioms. For each formula φ(x, y₁, …, y_k) in the language of Peano arithmetic, the first-order induction axiom for φ is the sentence

{\displaystyle \forall {\bar {y}}((\varphi (0,{\bar {y}})\land \forall x(\varphi (x,{\bar {y}})\Rightarrow \varphi (S(x),{\bar {y}})))\Rightarrow \forall x\varphi (x,{\bar {y}}))}

where {\displaystyle {\bar {y}}} is an abbreviation for y₁,…,y_k. The first-order induction schema includes every instance of the first-order induction axiom, that is, it includes the induction axiom for every formula φ.

Equivalent axiomatizations[edit]

There are many different, but equivalent, axiomatizations of Peano arithmetic. While some axiomatizations, such as the one just described, use a signature that only has symbols for 0 and the successor, addition, and multiplications operations, other axiomatizations use the language of ordered semirings, including an additional order relation symbol. One such axiomatization begins with the following axioms that describe a discrete ordered semiring.^[10]

1. {\displaystyle \forall x,y,z\ ((x+y)+z=x+(y+z))}, i.e., addition is associative.
2. {\displaystyle \forall x,y\ (x+y=y+x)}, i.e., addition is commutative.
3. {\displaystyle \forall x,y,z\ ((x\cdot y)\cdot z=x\cdot (y\cdot z))}, i.e., multiplication is associative.
4. {\displaystyle \forall x,y\ (x\cdot y=y\cdot x)}, i.e., multiplication is commutative.
5. {\displaystyle \forall x,y,z\ (x\cdot (y+z)=(x\cdot y)+(x\cdot z))}, i.e., multiplication distributes over addition.
6. {\displaystyle \forall x\ (x+0=x\land x\cdot 0=0)}, i.e., zero is an identity for addition, and an absorbing element for multiplication (actually superfluous^{[note 1]}).
7. {\displaystyle \forall x\ (x\cdot 1=x)}, i.e., one is an identity for multiplication.
8. {\displaystyle \forall x,y,z\ (x<y\land y<z\Rightarrow x<z)}, i.e., the ‘<‘ operator is transitive.
9. {\displaystyle \forall x\ (\neg (x<x))}, i.e., the ‘<‘ operator is irreflexive.
10. {\displaystyle \forall x,y\ (x<y\lor x=y\lor y<x)}, i.e., the ordering satisfies trichotomy.
11. {\displaystyle \forall x,y,z\ (x<y\Rightarrow x+z<y+z)}, i.e. the ordering is preserved under addition of the same element.
12. {\displaystyle \forall x,y,z\ (0<z\land x<y\Rightarrow x\cdot z<y\cdot z)}, i.e. the ordering is preserved under multiplication by the same positive element.
13. {\displaystyle \forall x,y\ (x<y\Rightarrow \exists z\ (x+z=y))}, i.e. given any two distinct elements, the larger is the smaller plus another element.
14. {\displaystyle 0<1\land \forall x\ (x>0\Rightarrow x\geq 1)}, i.e. zero and one are distinct and there is no element between them.
15. {\displaystyle \forall x\ (x\geq 0)}, i.e. zero is the minimum element.

The theory defined by these axioms is known as PA⁻; the theory PA is obtained by adding the first-order induction schema. An important property of PA⁻ is that any structure {\displaystyle M} satisfying this theory has an initial segment (ordered by {\displaystyle \leq }) isomorphic to {\displaystyle \mathbf {N} }. Elements in that segment are called standard elements, while other elements are called nonstandard elements.

Models[edit]

A model of the Peano axioms is a triple (N, 0, S), where N is a (necessarily infinite) set, 0 ∈ N and S: N → N satisfies the axioms above. Dedekind proved in his 1888 book, The Nature and Meaning of Numbers (German: Was sind und was sollen die Zahlen?, i.e., “What are the numbers and what are they good for?”) that any two models of the Peano axioms (including the second-order induction axiom) are isomorphic. In particular, given two models (N_A, 0_A, S_A) and (N_B, 0_B, S_B) of the Peano axioms, there is a unique homomorphism f : N_A → N_B satisfying

{\displaystyle {\begin{aligned}f(0_{A})&=0_{B}\\f(S_{A}(n))&=S_{B}(f(n))\end{aligned}}}

and it is a bijection. This means that the second-order Peano axioms are categorical. This is not the case with any first-order reformulation of the Peano axioms, however.

Set-theoretic models[edit]

The Peano axioms can be derived from set theoretic constructions of the natural numbers and axioms of set theory such as ZF.^[11] The standard construction of the naturals, due to John von Neumann, starts from a definition of 0 as the empty set, ∅, and an operator s on sets defined as:

{\displaystyle s(a)=a\cup \{a\}}

The set of natural numbers N is defined as the intersection of all sets closed under s that contain the empty set. Each natural number is equal (as a set) to the set of natural numbers less than it:

{\displaystyle {\begin{aligned}0&=\emptyset \\1&=s(0)=s(\emptyset )=\emptyset \cup \{\emptyset \}=\{\emptyset \}=\{0\}\\2&=s(1)=s(\{0\})=\{0\}\cup \{\{0\}\}=\{0,\{0\}\}=\{0,1\}\\3&=s(2)=s(\{0,1\})=\{0,1\}\cup \{\{0,1\}\}=\{0,1,\{0,1\}\}=\{0,1,2\}\end{aligned}}}

and so on. The set N together with 0 and the successor function s : N → N satisfies the Peano axioms.

Peano arithmetic is equiconsistent with several weak systems of set theory.^[12] One such system is ZFC with the axiom of infinity replaced by its negation. Another such system consists of general set theory (extensionality, existence of the empty set, and the axiom of adjunction), augmented by an axiom schema stating that a property that holds for the empty set and holds of an adjunction whenever it holds of the adjunct must hold for all sets.

Interpretation in category theory[edit]

The Peano axioms can also be understood using category theory. Let C be a category with terminal object 1_C, and define the category of pointed unary systems, US₁(C) as follows:

• The objects of US₁(C) are triples (X, 0_X, S_X) where X is an object of C, and 0_X : 1_C → X and S_X : X → X are C-morphisms.
• A morphism φ : (X, 0_X, S_X) → (Y, 0_Y, S_Y) is a C-morphism φ : X → Y with φ 0_X = 0_Y and φ S_X = S_Y φ.

Then C is said to satisfy the Dedekind–Peano axioms if US₁(C) has an initial object; this initial object is known as a natural number object in C. If (N, 0, S) is this initial object, and (X, 0_X, S_X) is any other object, then the unique map u : (N, 0, S) → (X, 0_X, S_X) is such that

{\displaystyle {\begin{aligned}u0&=0_{X},\\u(Sx)&=S_{X}(ux).\end{aligned}}}

This is precisely the recursive definition of 0_X and S_X.

Nonstandard models[edit]

Although the usual natural numbers satisfy the axioms of PA, there are other models as well (called “non-standard models“); the compactness theorem implies that the existence of nonstandard elements cannot be excluded in first-order logic.^[13] The upward Löwenheim–Skolem theorem shows that there are nonstandard models of PA of all infinite cardinalities. This is not the case for the original (second-order) Peano axioms, which have only one model, up to isomorphism.^[14] This illustrates one way the first-order system PA is weaker than the second-order Peano axioms.

When interpreted as a proof within a first-order set theory, such as ZFC, Dedekind’s categoricity proof for PA shows that each model of set theory has a unique model of the Peano axioms, up to isomorphism, that embeds as an initial segment of all other models of PA contained within that model of set theory. In the standard model of set theory, this smallest model of PA is the standard model of PA; however, in a nonstandard model of set theory, it may be a nonstandard model of PA. This situation cannot be avoided with any first-order formalization of set theory.

It is natural to ask whether a countable nonstandard model can be explicitly constructed. The answer is affirmative as Skolem in 1933 provided an explicit construction of such a nonstandard model. On the other hand, Tennenbaum’s theorem, proved in 1959, shows that there is no countable nonstandard model of PA in which either the addition or multiplication operation is computable.^[15] This result shows it is difficult to be completely explicit in describing the addition and multiplication operations of a countable nonstandard model of PA. There is only one possible order type of a countable nonstandard model. Letting ω be the order type of the natural numbers, ζ be the order type of the integers, and η be the order type of the rationals, the order type of any countable nonstandard model of PA is ω + ζ·η, which can be visualized as a copy of the natural numbers followed by a dense linear ordering of copies of the integers.

Overspill[edit]

A cut in a nonstandard model M is a nonempty subset C of M so that C is downward closed (x < y and y ∈ C ⇒ x ∈ C) and C is closed under successor. A proper cut is a cut that is a proper subset of M. Each nonstandard model has many proper cuts, including one that corresponds to the standard natural numbers. However, the induction scheme in Peano arithmetic prevents any proper cut from being definable. The overspill lemma, first proved by Abraham Robinson, formalizes this fact.

Overspill Lemma^[16] Let M be a nonstandard model of PA and let C be a proper cut of M. Suppose that {\displaystyle {\bar {a}}} is a tuple of elements of M and {\displaystyle \phi (x,{\bar {a}})} is a formula in the language of arithmetic so that

{\displaystyle M\vDash \phi (b,{\bar {a}})} for all b ∈ C.

Then there is a c in M that is greater than every element of C such that

{\displaystyle M\vDash \phi (c,{\bar {a}}).}

Consistency[edit]

When the Peano axioms were first proposed, Bertrand Russell and others agreed that these axioms implicitly defined what we mean by a “natural number”.^[17] Henri Poincaré was more cautious, saying they only defined natural numbers if they were consistent; if there is a proof that starts from just these axioms and derives a contradiction such as 0 = 1, then the axioms are inconsistent, and don’t define anything.^[18] In 1900, David Hilbert posed the problem of proving their consistency using only finitistic methods as the second of his twenty-three problems.^[19] In 1931, Kurt Gödel proved his second incompleteness theorem, which shows that such a consistency proof cannot be formalized within Peano arithmetic itself.^[20]

Although it is widely claimed that Gödel’s theorem rules out the possibility of a finitistic consistency proof for Peano arithmetic, this depends on exactly what one means by a finitistic proof. Gödel himself pointed out the possibility of giving a finitistic consistency proof of Peano arithmetic or stronger systems by using finitistic methods that are not formalizable in Peano arithmetic, and in 1958, Gödel published a method for proving the consistency of arithmetic using type theory.^[21] In 1936, Gerhard Gentzen gave a proof of the consistency of Peano’s axioms, using transfinite induction up to an ordinal called ε₀.^[22] Gentzen explained: “The aim of the present paper is to prove the consistency of elementary number theory or, rather, to reduce the question of consistency to certain fundamental principles”. Gentzen’s proof is arguably finitistic, since the transfinite ordinal ε₀ can be encoded in terms of finite objects (for example, as a Turing machine describing a suitable order on the integers, or more abstractly as consisting of the finite trees, suitably linearly ordered). Whether or not Gentzen’s proof meets the requirements Hilbert envisioned is unclear: there is no generally accepted definition of exactly what is meant by a finitistic proof, and Hilbert himself never gave a precise definition.

The vast majority of contemporary mathematicians believe that Peano’s axioms are consistent, relying either on intuition or the acceptance of a consistency proof such as Gentzen’s proof. A small number of philosophers and mathematicians, some of whom also advocate ultrafinitism, reject Peano’s axioms because accepting the axioms amounts to accepting the infinite collection of natural numbers. In particular, addition (including the successor function) and multiplication are assumed to be total. Curiously, there are self-verifying theories that are similar to PA but have subtraction and division instead of addition and multiplication, which are axiomatized in such a way to avoid proving sentences that correspond to the totality of addition and multiplication, but which are still able to prove all true {\displaystyle \Pi _{1}} theorems of PA, and yet can be extended to a consistent theory that proves its own consistency (stated as the non-existence of a Hilbert-style proof of “0=1”).^[23]

See also[edit]

• Foundations of mathematics
• Frege’s theorem
• Goodstein’s theorem
• Neo-logicism
• Non-standard model of arithmetic
• Paris–Harrington theorem
• Presburger arithmetic
• Robinson arithmetic
• Second-order arithmetic
• Typographical Number Theory

Notes[edit]

[A]

https://www.youtube.com/watch?v=-Dx_STgFLLo

[B]

SEA

SSSSEEEEEEEEE SEA CCCCCCCC SEEEEE

[A]

]2]

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From: Biden for President
Date: Tue, Mar 3, 2020 at 6:36 PM
Subject: a lot on the line today
To: ajay mishra

There are more than one thousand delegates being awarded across the country and we need to win as many as possible.

‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ ajay, There’s a lot on the line today. There are more than one thousand delegates being awarded across the country, and we need to win as many as possible to seal the deal on making Joe the Democratic nominee. Can we count on you for $5 today? If you’ve saved payment information with ActBlue Express, your donation will go through immediately: $5 ➞ $25 ➞ $50 ➞ $100 ➞ $250 ➞ Other ➞ Let us break it down, ajay: IF we can bring in a surge of donations today, we’ll be in great shape to win the votes we need in strategic districts across the country. IF we can win in these districts, we’ll earn the delegate totals we need to secure the Democratic nomination and send Joe Biden to defeat Donald Trump. BUT we can only make all of this happen if all our supporters rally around our campaign today and make it happen! Your donation today can make a huge difference, ajay. Will you chip in $5 to make sure Joe Biden is our Democratic nominee come July? If you’ve saved payment information with ActBlue Express, your donation will go through immediately: $5 ➞ $25 ➞ $50 ➞ $100 ➞ $250 ➞ Other ➞ Thanks for standing with us, Biden for President

Any donor history information in this email reflects what we have on file for this specific email address. If you have donated with a different email, with a check, or with a spouse — thank you so much! We have that on file and cannot thank you enough for supporting this campaign. This email was sent to ajayinsead03. If we got your name or any information wrong — we’re so sorry! To update and correct your information click here. If you would like to receive fewer emails, click here. If you would like to unsubscribe, click here. ajay, thank you so much for supporting Joe Biden’s Presidential campaign. This isn’t the time to be complacent. If you are ready to fight for the soul of this nation, you can start by donating to elect Joe Biden by clicking the button below. DONATE TO ELECT JOE BIDEN » We know we send a lot of emails, and we are sorry about that. The reason? We are relying on grassroots supporters like you (we’re serious!). But ajay, we don’t want to bother you. If you’d like to only receive our most important emails, click here. If you’d only like to receive volunteer emails, click here. If you’d like to unsubscribe from our emails, you can click here. To make a contribution by mail, click here for instructions. We sincerely thank you for your help and support. – The entire Joe Biden for President team Paid for by Biden for President

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[1]

[2]

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 НазадВперёд 

OK OLGA – I CANT EXPLAIN BEYOND – THIS TILL EVERN AFTER 2030 ET ALONE 2020 BECAUSE I WANT SOME PRIVACY

BUBBA: SHIVA HAS HOW MANY FORMS -? T LEATS 25- ONE OFTHEM IS BHOLE NATH – ONE IS NEEKANATH MEANS MY MOM IS WHORE – BUT U KNOW BARACK ON TIMES CVER SID NATARAJ OR DID HE EXMBARCE PEACE EANS NEELKATH DAVID AND RAHM -> DOES THIS QAULIFY AS SHORT BUT LONG ENOUGH TO CHEW ON ? – ME IS MEANS – WHEN CHOICE WAS PRESENTED TO ACCEPT HE NOBLE AWARD U RAHM SAID – ITS CALL FOR ACTION AND AT ACCEPTANCE DID OUR BOY SAID AND VEOKED MAHABHARAT CALED THE JUST WAR – I MENA THE JIHAD TRSNALTION IN HINDU IS CALELD GEETA HAS MAHABHARAT AND DARHMA MEANS JUST WAR – MEANS – YADA YADA HI DAHRMASAY GLAIR BHAVAITA BAHARTA – ABYUTHANAMA MA DAHRMA’S TADATMA NUM SRAJA MYHAUM – IS CALED SHANK IN HINDU – AND SHOFAR IN HEBEW – RAHM

– ALSO CALLLED – THERE IS SEASON U SAID DEADFISH AND SCHOED YOUR FINGERS IN A SHARPED TWIST – OK RAHM- BUT DO U KNOW LIKE SENATOR FROM PUNAJAB – IS PAOSIITNINING ITEM SONG – WENT HARD ON SOME PEOPLES -MOM – THERE IS SIMILALRLY ALSO CALED WORD CALELD PAUL SAMUELSON THE JEW WHO WAS FIRST AMERICAN WHO WON THE NOBLE IN ECON – ME MEANS ARAHM EMANUEL BHAI MERE A- WREVALED PREFENRECS

IN HINDU OAND ENGLSIH IS ACELD WHEN PSUH COMES TO SHOVE DID U CHOSOE NEEKHANT OR DID U SAY -YEAH – ON TIME FRONT PGE COVER – ME IS CAELD NATARAJ ? – > IF I SY MORE – THEN – MAYBE DAVID CANT UNDERATND

– BUT RAHM – DO U KNOW WOR D YONI – ? OK DO U KNOW WORD YONI NETANAYHU IS CALED RASPOUTIN IN RUSSHIA AND GANDHI IN LUCKNOW – RAHM ? I MEAN U MOVED FURNITURE AT IDF – AND GUESS RAHM – WHERE’S MY CAR ?

I CANT SAY MORE BUBBA – I SPECIALLY CANT BECAUSE WHEN GANDHI AROVED TO SUA LIKE EEEDIE MUROHY – DID ONCEOUPON – HE WAS MEEMERIZED BY BNOT JUST BUSINESS SPEPLES JARGON UT LASO HOW JIMMY AND U GUYS POLITICIAIANS PEROSN SPOKE –

I MEANS – REALLY BUBBA – TELL BARCK AND HIS CAMP – THAT SHIVA HAS 25 MORPHOLOGIES T LEAST – SO, NEEKATH AND NATRAJ ARE TWO N FWORDS – U CAN ADD IN THE VOCBULARY OF BARACK

AND TELL HIM THAT AGANDHI SAID – – WHAT? – YEAH – LIKE MLK INTERPREETE – GANDHI SAID – WHAT BUBBA ?WHEN MK WS ASKED – WHAT IS THE ONLY ALETRNATIVE?

LET ME EXPLAIN LIKE BRAHMINS DO BUBBA

[A] U KNOW BLOLLEAN AND NON BOOLEAN AND HOSEIAN AND NON HOBESIAN CHOICE DINENR MENU?

[B] N FOR NEEKANTH OR N FOR NARTARAJ

[C] N FORWHICH NUBER OF SHIVA IS U WANTS – MY MAN ? TEL ME

ME IS MEANS N FOR NESHER

OR

N FOR N FOR NO SHER

IS A CHOICE

AND

A MENU IN

LUNCH

BREAK FAST AND  IN DINNER